45-5(3-7z)=20z+4(z+2)

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Solution for 45-5(3-7z)=20z+4(z+2) equation: 



45-5(3-7z)=20z+4(z+2)

We move all terms to the left:

45-5(3-7z)-(20z+4(z+2))=0

We add all the numbers together, and all the variables

-5(-7z+3)-(20z+4(z+2))+45=0

We multiply parentheses

35z-(20z+4(z+2))-15+45=0



We calculate terms in parentheses: -(20z+4(z+2)), so:

20z+4(z+2)

We multiply parentheses

20z+4z+8

We add all the numbers together, and all the variables

24z+8

Back to the equation:

-(24z+8)



We add all the numbers together, and all the variables

35z-(24z+8)+30=0

We get rid of parentheses

35z-24z-8+30=0

We add all the numbers together, and all the variables

11z+22=0

We move all terms containing z to the left, all other terms to the right

11z=-22

z=-22/11

z=-2

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