45-9(2c+3)=4(c+7)+c

Solution for 45-9(2c+3)=4(c+7)+c equation:

45-9(2c+3)=4(c+7)+c

We move all terms to the left:

45-9(2c+3)-(4(c+7)+c)=0

We multiply parentheses

-18c-(4(c+7)+c)-27+45=0


We calculate terms in parentheses: -(4(c+7)+c), so:

4(c+7)+c

We add all the numbers together, and all the variables

c+4(c+7)

We multiply parentheses

c+4c+28

We add all the numbers together, and all the variables

5c+28

Back to the equation:

-(5c+28)


We add all the numbers together, and all the variables

-18c-(5c+28)+18=0

We get rid of parentheses

-18c-5c-28+18=0

We add all the numbers together, and all the variables

-23c-10=0

We move all terms containing c to the left, all other terms to the right

-23c=10

c=10/-23

c=-10/23