45/p+p=18p=7/4=4

Solution for 45/p+p=18p=7/4=4 equation:

45/p+p=18p=7/4=4

We move all terms to the left:

45/p+p-(18p)=0


Domain of the equation: p!=0

p∈R


We add all the numbers together, and all the variables

-17p+45/p=0

We multiply all the terms by the denominator


-17p*p+45=0

Wy multiply elements

-17p^2+45=0

a = -17; b = 0; c = +45;
Δ = b2-4ac
Δ = 02-4·(-17)·45
Δ = 3060
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{3060}=\sqrt{36*85}=\sqrt{36}*\sqrt{85}=6\sqrt{85}$
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-6\sqrt{85}}{2*-17}=\frac{0-6\sqrt{85}}{-34}
=-\frac{6\sqrt{85}}{-34}
=-\frac{3\sqrt{85}}{-17}
$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+6\sqrt{85}}{2*-17}=\frac{0+6\sqrt{85}}{-34}
=\frac{6\sqrt{85}}{-34}
=\frac{3\sqrt{85}}{-17}
$