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45=(1)/(9)(90-x)
We move all terms to the left:
45-((1)/(9)(90-x))=0
Domain of the equation: 9(90-x))!=0We add all the numbers together, and all the variables
x∈R
-(1/9(-1x+90))+45=0
We multiply all the terms by the denominator
-(1+45*9(-1x+90))=0
We calculate terms in parentheses: -(1+45*9(-1x+90)), so:
1+45*9(-1x+90)
determiningTheFunctionDomain 45*9(-1x+90)+1
Wy multiply elements
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We use the square of the difference formula
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Back to the equation:
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| 7(x−7)−4=18x−141 | | 3/14+q=3/4 | | 7=1/3(8x=6) | | 48x-64x^2=9 | | 2/5x+6=0 | | 7=1/3(=6)8x | | -17.96+8.2q+12.52=6.8q-15.38 | | 8x-2-4=x-5 | | b=2b-14 | | 9c+16+20=-18+6c | | -16-u=20-4u | | x-3/15=7/15 | | -(2x+6)+9x=-32 | | -8(5+x)=139 | | 40/y=-4y= | | -2 | | −7.8r=−1.56 | | 4b+13/2=0 | | -18x-14=-104-18x= | | 8x43=93-3x | | 46-u=247 | | 3/8x+1/4=1/2 | | 9-(1-2y)=4+y+5(3-y) | | Z+15=5z+9 | | 0x-66=129-3x | | 56=8(10+n) | | x+2.7=8.1 | | 1/3x+2/3=20/27 | | D=38t+220 | | 2,5/x+4=4,5 | | 2x+5(/3)=3 | | X+28=3x-8 |