45=-2(5a-5)+5(1+4a)

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Solution for 45=-2(5a-5)+5(1+4a) equation: 



45=-2(5a-5)+5(1+4a)

We move all terms to the left:

45-(-2(5a-5)+5(1+4a))=0

We add all the numbers together, and all the variables

-(-2(5a-5)+5(4a+1))+45=0



We calculate terms in parentheses: -(-2(5a-5)+5(4a+1)), so:

-2(5a-5)+5(4a+1)

We multiply parentheses

-10a+20a+10+5

We add all the numbers together, and all the variables

10a+15

Back to the equation:

-(10a+15)



We get rid of parentheses

-10a-15+45=0

We add all the numbers together, and all the variables

-10a+30=0

We move all terms containing a to the left, all other terms to the right

-10a=-30

a=-30/-10

a=+3

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