45=2b+3(17-b)

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Solution for 45=2b+3(17-b) equation: 



45=2b+3(17-b)

We move all terms to the left:

45-(2b+3(17-b))=0

We add all the numbers together, and all the variables

-(2b+3(-1b+17))+45=0



We calculate terms in parentheses: -(2b+3(-1b+17)), so:

2b+3(-1b+17)

We multiply parentheses

2b-3b+51

We add all the numbers together, and all the variables

-1b+51

Back to the equation:

-(-1b+51)



We get rid of parentheses

1b-51+45=0

We add all the numbers together, and all the variables

b-6=0

We move all terms containing b to the left, all other terms to the right

b=6

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