If it's not what You are looking for type in the equation solver your own equation and let us solve it.
45=2n^2-5n+3
We move all terms to the left:
45-(2n^2-5n+3)=0
We get rid of parentheses
-2n^2+5n-3+45=0
We add all the numbers together, and all the variables
-2n^2+5n+42=0
a = -2; b = 5; c = +42;
Δ = b2-4ac
Δ = 52-4·(-2)·42
Δ = 361
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{361}=19$$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(5)-19}{2*-2}=\frac{-24}{-4} =+6 $$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(5)+19}{2*-2}=\frac{14}{-4} =-3+1/2 $
| -n-3-5+2n=9 | | 6x+9=11x+9+120 | | 5x+3x-3=10x-2x-3 | | -6(6x+5)-3+4x=-408+x | | 7+.75x=2.80 | | 3k+2−10k=-6k+8 | | 16x+96=144 | | 7w−10=6w | | -4+r+4+2r=9 | | -4u=-u+6 | | 259=-7(-7+5a) | | -10+4n=10−n | | 7t+10=2+6t | | (2c/11)=(c-3/4) | | -6x-4x=70 | | 8g+10=9g | | -3(1+7x)=39 | | -6v+7−2v=1−6v | | 11/3x=3/2 | | -6f+7−2f=1−6f | | -6p-4p=14 | | 1.53=r−15.5 | | -3v=-5−2v | | (3+4x)(9-12x+16x^2)-16x(4x^2-1)=-5 | | 3u+5=-4+2u | | 2(4-6x)=44 | | (5/x)+(12/x-8)+3=0 | | 118=-x-2(-8+1) | | 261=208-w | | 6x-5x+9=21 | | -5(1-2x)-4(7x+3)=-53 | | 12x+20=20x+10 |