45=5(2n-1)

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Solution for 45=5(2n-1) equation: 



45=5(2n-1)

We move all terms to the left:

45-(5(2n-1))=0



We calculate terms in parentheses: -(5(2n-1)), so:

5(2n-1)

We multiply parentheses

10n-5

Back to the equation:

-(10n-5)



We get rid of parentheses

-10n+5+45=0

We add all the numbers together, and all the variables

-10n+50=0

We move all terms containing n to the left, all other terms to the right

-10n=-50

n=-50/-10

n=+5

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