45n-4(12n-3)=9-3(n-1)

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Solution for 45n-4(12n-3)=9-3(n-1) equation:


Simplifying
45n + -4(12n + -3) = 9 + -3(n + -1)

Reorder the terms:
45n + -4(-3 + 12n) = 9 + -3(n + -1)
45n + (-3 * -4 + 12n * -4) = 9 + -3(n + -1)
45n + (12 + -48n) = 9 + -3(n + -1)

Reorder the terms:
12 + 45n + -48n = 9 + -3(n + -1)

Combine like terms: 45n + -48n = -3n
12 + -3n = 9 + -3(n + -1)

Reorder the terms:
12 + -3n = 9 + -3(-1 + n)
12 + -3n = 9 + (-1 * -3 + n * -3)
12 + -3n = 9 + (3 + -3n)

Combine like terms: 9 + 3 = 12
12 + -3n = 12 + -3n

Add '-12' to each side of the equation.
12 + -12 + -3n = 12 + -12 + -3n

Combine like terms: 12 + -12 = 0
0 + -3n = 12 + -12 + -3n
-3n = 12 + -12 + -3n

Combine like terms: 12 + -12 = 0
-3n = 0 + -3n
-3n = -3n

Add '3n' to each side of the equation.
-3n + 3n = -3n + 3n

Combine like terms: -3n + 3n = 0
0 = -3n + 3n

Combine like terms: -3n + 3n = 0
0 = 0

Solving
0 = 0

Couldn't find a variable to solve for.

This equation is an identity, all real numbers are solutions.

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