45x-(23x+15)+8=(17x-9)+3x-(x+74)

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Solution for 45x-(23x+15)+8=(17x-9)+3x-(x+74) equation: 



45x-(23x+15)+8=(17x-9)+3x-(x+74)

We move all terms to the left:

45x-(23x+15)+8-((17x-9)+3x-(x+74))=0

We get rid of parentheses

45x-23x-((17x-9)+3x-(x+74))-15+8=0



We calculate terms in parentheses: -((17x-9)+3x-(x+74)), so:

(17x-9)+3x-(x+74)

We add all the numbers together, and all the variables

3x+(17x-9)-(x+74)

We get rid of parentheses

3x+17x-x-9-74

We add all the numbers together, and all the variables

19x-83

Back to the equation:

-(19x-83)



We add all the numbers together, and all the variables

22x-(19x-83)-7=0

We get rid of parentheses

22x-19x+83-7=0

We add all the numbers together, and all the variables

3x+76=0

We move all terms containing x to the left, all other terms to the right

3x=-76

x=-76/3

x=-25+1/3

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