45x-1=(32x-8)+10x

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Solution for 45x-1=(32x-8)+10x equation: 



45x-1=(32x-8)+10x

We move all terms to the left:

45x-1-((32x-8)+10x)=0



We calculate terms in parentheses: -((32x-8)+10x), so:

(32x-8)+10x

We add all the numbers together, and all the variables

10x+(32x-8)

We get rid of parentheses

10x+32x-8

We add all the numbers together, and all the variables

42x-8

Back to the equation:

-(42x-8)



We get rid of parentheses

45x-42x+8-1=0

We add all the numbers together, and all the variables

3x+7=0

We move all terms containing x to the left, all other terms to the right

3x=-7

x=-7/3

x=-2+1/3

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