46-(2c+4)=4(c-7)+c

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Solution for 46-(2c+4)=4(c-7)+c equation: 



46-(2c+4)=4(c-7)+c

We move all terms to the left:

46-(2c+4)-(4(c-7)+c)=0

We get rid of parentheses

-2c-(4(c-7)+c)-4+46=0



We calculate terms in parentheses: -(4(c-7)+c), so:

4(c-7)+c

We add all the numbers together, and all the variables

c+4(c-7)

We multiply parentheses

c+4c-28

We add all the numbers together, and all the variables

5c-28

Back to the equation:

-(5c-28)



We add all the numbers together, and all the variables

-2c-(5c-28)+42=0

We get rid of parentheses

-2c-5c+28+42=0

We add all the numbers together, and all the variables

-7c+70=0

We move all terms containing c to the left, all other terms to the right

-7c=-70

c=-70/-7

c=+10

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