46-(3c+4)=2(c+6)

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Solution for 46-(3c+4)=2(c+6) equation: 



46-(3c+4)=2(c+6)

We move all terms to the left:

46-(3c+4)-(2(c+6))=0

We get rid of parentheses

-3c-(2(c+6))-4+46=0



We calculate terms in parentheses: -(2(c+6)), so:

2(c+6)

We multiply parentheses

2c+12

Back to the equation:

-(2c+12)



We add all the numbers together, and all the variables

-3c-(2c+12)+42=0

We get rid of parentheses

-3c-2c-12+42=0

We add all the numbers together, and all the variables

-5c+30=0

We move all terms containing c to the left, all other terms to the right

-5c=-30

c=-30/-5

c=+6

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