46-1(2c+4)=4(c-7)+c

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Solution for 46-1(2c+4)=4(c-7)+c equation: 



46-1(2c+4)=4(c-7)+c

We move all terms to the left:

46-1(2c+4)-(4(c-7)+c)=0



We calculate terms in parentheses: -(4(c-7)+c), so:

4(c-7)+c

We add all the numbers together, and all the variables

c+4(c-7)

We multiply parentheses

c+4c-28

We add all the numbers together, and all the variables

5c-28

Back to the equation:

-(5c-28)



We get rid of parentheses

-1(2c+4)-5c+28+46=0

We add all the numbers together, and all the variables

-5c-1(2c+4)+74=0

We move all terms containing c to the left, all other terms to the right

-5c-1(2c+4)=-74

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