46=(2x+3)+(x+2)

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Solution for 46=(2x+3)+(x+2) equation: 



46=(2x+3)+(x+2)

We move all terms to the left:

46-((2x+3)+(x+2))=0



We calculate terms in parentheses: -((2x+3)+(x+2)), so:

(2x+3)+(x+2)

We get rid of parentheses

2x+x+3+2

We add all the numbers together, and all the variables

3x+5

Back to the equation:

-(3x+5)



We get rid of parentheses

-3x-5+46=0

We add all the numbers together, and all the variables

-3x+41=0

We move all terms containing x to the left, all other terms to the right

-3x=-41

x=-41/-3

x=13+2/3

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