46=(3x/2)-3+2x

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Solution for 46=(3x/2)-3+2x equation: 



46=(3x/2)-3+2x

We move all terms to the left:

46-((3x/2)-3+2x)=0



Domain of the equation: 2)-3+2x)!=0

x!=0/1

x!=0

x∈R



We add all the numbers together, and all the variables

-((+3x/2)-3+2x)+46=0

We multiply all the terms by the denominator


-((+3x+46*2)-3+2x)=0



We calculate terms in parentheses: -((+3x+46*2)-3+2x), so:

(+3x+46*2)-3+2x

determiningTheFunctionDomain
(+3x+46*2)+2x-3

We add all the numbers together, and all the variables

(3x+92)+2x-3

We add all the numbers together, and all the variables

2x+(3x+92)-3

We get rid of parentheses

2x+3x+92-3

We add all the numbers together, and all the variables

5x+89

Back to the equation:

-(5x+89)



We get rid of parentheses

-5x-89=0

We move all terms containing x to the left, all other terms to the right

-5x=89

x=89/-5

x=-17+4/5

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