46=1/2(x+2)(3x+15)

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Solution for 46=1/2(x+2)(3x+15) equation: 



46=1/2(x+2)(3x+15)

We move all terms to the left:

46-(1/2(x+2)(3x+15))=0



Domain of the equation: 2(x+2)(3x+15))!=0

x∈R



We multiply parentheses ..

-(1/2(+3x^2+15x+6x+30))+46=0

We multiply all the terms by the denominator


-(1+46*2(+3x^2+15x+6x+30))=0



We calculate terms in parentheses: -(1+46*2(+3x^2+15x+6x+30)), so:

1+46*2(+3x^2+15x+6x+30)

determiningTheFunctionDomain
46*2(+3x^2+15x+6x+30)+1

Wy multiply elements

92x(++1

We use the square of the difference formula

92x(+1

Back to the equation:

-(92x(+1)



We add all the numbers together, and all the variables

-(92x1=0

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