46=2(3+3b)+4b

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Solution for 46=2(3+3b)+4b equation: 



46=2(3+3b)+4b

We move all terms to the left:

46-(2(3+3b)+4b)=0

We add all the numbers together, and all the variables

-(2(3b+3)+4b)+46=0



We calculate terms in parentheses: -(2(3b+3)+4b), so:

2(3b+3)+4b

We add all the numbers together, and all the variables

4b+2(3b+3)

We multiply parentheses

4b+6b+6

We add all the numbers together, and all the variables

10b+6

Back to the equation:

-(10b+6)



We get rid of parentheses

-10b-6+46=0

We add all the numbers together, and all the variables

-10b+40=0

We move all terms containing b to the left, all other terms to the right

-10b=-40

b=-40/-10

b=+4

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