47+(10+3x)=90

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Solution for 47+(10+3x)=90 equation: 



47+(10+3x)=90

We move all terms to the left:

47+(10+3x)-(90)=0

We add all the numbers together, and all the variables

(3x+10)+47-90=0

We add all the numbers together, and all the variables

(3x+10)-43=0

We get rid of parentheses

3x+10-43=0

We add all the numbers together, and all the variables

3x-33=0

We move all terms containing x to the left, all other terms to the right

3x=33

x=33/3

x=11

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