47+3x+10=9x+39

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Solution for 47+3x+10=9x+39 equation: 



47+3x+10=9x+39

We move all terms to the left:

47+3x+10-(9x+39)=0

We add all the numbers together, and all the variables

3x-(9x+39)+57=0

We get rid of parentheses

3x-9x-39+57=0

We add all the numbers together, and all the variables

-6x+18=0

We move all terms containing x to the left, all other terms to the right

-6x=-18

x=-18/-6

x=+3

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