47+3x+10=9x+39

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Solution for 47+3x+10=9x+39 equation:



47+3x+10=9x+39
We move all terms to the left:
47+3x+10-(9x+39)=0
We add all the numbers together, and all the variables
3x-(9x+39)+57=0
We get rid of parentheses
3x-9x-39+57=0
We add all the numbers together, and all the variables
-6x+18=0
We move all terms containing x to the left, all other terms to the right
-6x=-18
x=-18/-6
x=+3

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