47+3x+10=9x-36

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Solution for 47+3x+10=9x-36 equation: 



47+3x+10=9x-36

We move all terms to the left:

47+3x+10-(9x-36)=0

We add all the numbers together, and all the variables

3x-(9x-36)+57=0

We get rid of parentheses

3x-9x+36+57=0

We add all the numbers together, and all the variables

-6x+93=0

We move all terms containing x to the left, all other terms to the right

-6x=-93

x=-93/-6

x=15+1/2

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