47+3y-19=12y-14-2y

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Solution for 47+3y-19=12y-14-2y equation: 



47+3y-19=12y-14-2y

We move all terms to the left:

47+3y-19-(12y-14-2y)=0

We add all the numbers together, and all the variables

3y-(10y-14)+47-19=0

We add all the numbers together, and all the variables

3y-(10y-14)+28=0

We get rid of parentheses

3y-10y+14+28=0

We add all the numbers together, and all the variables

-7y+42=0

We move all terms containing y to the left, all other terms to the right

-7y=-42

y=-42/-7

y=+6

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