47-(b+5)=29

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Solution for 47-(b+5)=29 equation: 



47-(b+5)=29

We move all terms to the left:

47-(b+5)-(29)=0

We add all the numbers together, and all the variables

-(b+5)+18=0

We get rid of parentheses

-b-5+18=0

We add all the numbers together, and all the variables

-1b+13=0

We move all terms containing b to the left, all other terms to the right

-b=-13

b=-13/-1

b=+13

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