47=(2a-3)+2a+(3a+1)

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Solution for 47=(2a-3)+2a+(3a+1) equation: 



47=(2a-3)+2a+(3a+1)

We move all terms to the left:

47-((2a-3)+2a+(3a+1))=0



We calculate terms in parentheses: -((2a-3)+2a+(3a+1)), so:

(2a-3)+2a+(3a+1)

We add all the numbers together, and all the variables

2a+(2a-3)+(3a+1)

We get rid of parentheses

2a+2a+3a-3+1

We add all the numbers together, and all the variables

7a-2

Back to the equation:

-(7a-2)



We get rid of parentheses

-7a+2+47=0

We add all the numbers together, and all the variables

-7a+49=0

We move all terms containing a to the left, all other terms to the right

-7a=-49

a=-49/-7

a=+7

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