47=(4y-3)+(3y+1)

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Solution for 47=(4y-3)+(3y+1) equation: 



47=(4y-3)+(3y+1)

We move all terms to the left:

47-((4y-3)+(3y+1))=0



We calculate terms in parentheses: -((4y-3)+(3y+1)), so:

(4y-3)+(3y+1)

We get rid of parentheses

4y+3y-3+1

We add all the numbers together, and all the variables

7y-2

Back to the equation:

-(7y-2)



We get rid of parentheses

-7y+2+47=0

We add all the numbers together, and all the variables

-7y+49=0

We move all terms containing y to the left, all other terms to the right

-7y=-49

y=-49/-7

y=+7

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