47=4(n-5)+5(-3n-2)

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Solution for 47=4(n-5)+5(-3n-2) equation: 



47=4(n-5)+5(-3n-2)

We move all terms to the left:

47-(4(n-5)+5(-3n-2))=0



We calculate terms in parentheses: -(4(n-5)+5(-3n-2)), so:

4(n-5)+5(-3n-2)

We multiply parentheses

4n-15n-20-10

We add all the numbers together, and all the variables

-11n-30

Back to the equation:

-(-11n-30)



We get rid of parentheses

11n+30+47=0

We add all the numbers together, and all the variables

11n+77=0

We move all terms containing n to the left, all other terms to the right

11n=-77

n=-77/11

n=-7

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