47=4y+3(1+6y)

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Solution for 47=4y+3(1+6y) equation: 



47=4y+3(1+6y)

We move all terms to the left:

47-(4y+3(1+6y))=0

We add all the numbers together, and all the variables

-(4y+3(6y+1))+47=0



We calculate terms in parentheses: -(4y+3(6y+1)), so:

4y+3(6y+1)

We multiply parentheses

4y+18y+3

We add all the numbers together, and all the variables

22y+3

Back to the equation:

-(22y+3)



We get rid of parentheses

-22y-3+47=0

We add all the numbers together, and all the variables

-22y+44=0

We move all terms containing y to the left, all other terms to the right

-22y=-44

y=-44/-22

y=+2

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