47x-7(4x-3)=4(5x-2)

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Solution for 47x-7(4x-3)=4(5x-2) equation: 



47x-7(4x-3)=4(5x-2)

We move all terms to the left:

47x-7(4x-3)-(4(5x-2))=0

We multiply parentheses

47x-28x-(4(5x-2))+21=0



We calculate terms in parentheses: -(4(5x-2)), so:

4(5x-2)

We multiply parentheses

20x-8

Back to the equation:

-(20x-8)



We add all the numbers together, and all the variables

19x-(20x-8)+21=0

We get rid of parentheses

19x-20x+8+21=0

We add all the numbers together, and all the variables

-1x+29=0

We move all terms containing x to the left, all other terms to the right

-x=-29

x=-29/-1

x=+29

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