48(-3c+(-4))=4(c+5)+c

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Solution for 48(-3c+(-4))=4(c+5)+c equation: 



48(-3c+(-4))=4(c+5)+c

We move all terms to the left:

48(-3c+(-4))-(4(c+5)+c)=0



We calculate terms in parentheses: -(4(c+5)+c), so:

4(c+5)+c

We add all the numbers together, and all the variables

c+4(c+5)

We multiply parentheses

c+4c+20

We add all the numbers together, and all the variables

5c+20

Back to the equation:

-(5c+20)



We get rid of parentheses

48(-3c+(-4))-5c-20=0

We add all the numbers together, and all the variables

-5c+48(-3c+(-4))-20=0

We move all terms containing c to the left, all other terms to the right

-5c+48(-3c+(-4))=20

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