48+(6x-28)+(2x)=180

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Solution for 48+(6x-28)+(2x)=180 equation: 



48+(6x-28)+(2x)=180

We move all terms to the left:

48+(6x-28)+(2x)-(180)=0

We add all the numbers together, and all the variables

2x+(6x-28)-132=0

We get rid of parentheses

2x+6x-28-132=0

We add all the numbers together, and all the variables

8x-160=0

We move all terms containing x to the left, all other terms to the right

8x=160

x=160/8

x=20

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