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48+2x=x2
We move all terms to the left:
48+2x-(x2)=0
We add all the numbers together, and all the variables
-1x^2+2x+48=0
a = -1; b = 2; c = +48;
Δ = b2-4ac
Δ = 22-4·(-1)·48
Δ = 196
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{196}=14$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(2)-14}{2*-1}=\frac{-16}{-2} =+8 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(2)+14}{2*-1}=\frac{12}{-2} =-6 $
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