48+4y-16=12y-10-2y

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Solution for 48+4y-16=12y-10-2y equation: 



48+4y-16=12y-10-2y

We move all terms to the left:

48+4y-16-(12y-10-2y)=0

We add all the numbers together, and all the variables

4y-(10y-10)+48-16=0

We add all the numbers together, and all the variables

4y-(10y-10)+32=0

We get rid of parentheses

4y-10y+10+32=0

We add all the numbers together, and all the variables

-6y+42=0

We move all terms containing y to the left, all other terms to the right

-6y=-42

y=-42/-6

y=+7

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