48-(2c+3)=4(1c+6)+6

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Solution for 48-(2c+3)=4(1c+6)+6 equation:



48-(2c+3)=4(1c+6)+6
We move all terms to the left:
48-(2c+3)-(4(1c+6)+6)=0
We add all the numbers together, and all the variables
-(2c+3)-(4(c+6)+6)+48=0
We get rid of parentheses
-2c-(4(c+6)+6)-3+48=0
We calculate terms in parentheses: -(4(c+6)+6), so:
4(c+6)+6
We multiply parentheses
4c+24+6
We add all the numbers together, and all the variables
4c+30
Back to the equation:
-(4c+30)
We add all the numbers together, and all the variables
-2c-(4c+30)+45=0
We get rid of parentheses
-2c-4c-30+45=0
We add all the numbers together, and all the variables
-6c+15=0
We move all terms containing c to the left, all other terms to the right
-6c=-15
c=-15/-6
c=2+1/2

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