48-(2c+3)=4(1c+6)+6

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Solution for 48-(2c+3)=4(1c+6)+6 equation: 



48-(2c+3)=4(1c+6)+6

We move all terms to the left:

48-(2c+3)-(4(1c+6)+6)=0

We add all the numbers together, and all the variables

-(2c+3)-(4(c+6)+6)+48=0

We get rid of parentheses

-2c-(4(c+6)+6)-3+48=0



We calculate terms in parentheses: -(4(c+6)+6), so:

4(c+6)+6

We multiply parentheses

4c+24+6

We add all the numbers together, and all the variables

4c+30

Back to the equation:

-(4c+30)



We add all the numbers together, and all the variables

-2c-(4c+30)+45=0

We get rid of parentheses

-2c-4c-30+45=0

We add all the numbers together, and all the variables

-6c+15=0

We move all terms containing c to the left, all other terms to the right

-6c=-15

c=-15/-6

c=2+1/2

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