48-(3C+4)=4(C+5)c+

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Solution for 48-(3C+4)=4(C+5)c+ equation:



48-(3+4)=4(+5)C+
We move all terms to the left:
48-(3+4)-(4(+5)C+)=0
We add all the numbers together, and all the variables
-(45C+)+48-7=0
We add all the numbers together, and all the variables
-(45C+)+41=0
We get rid of parentheses
-45C+41-=0
We add all the numbers together, and all the variables
-45C=0
C=0/-45
C=0

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