48-(3c+2)=2(3c-12)

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Solution for 48-(3c+2)=2(3c-12) equation: 



48-(3c+2)=2(3c-12)

We move all terms to the left:

48-(3c+2)-(2(3c-12))=0

We get rid of parentheses

-3c-(2(3c-12))-2+48=0



We calculate terms in parentheses: -(2(3c-12)), so:

2(3c-12)

We multiply parentheses

6c-24

Back to the equation:

-(6c-24)



We add all the numbers together, and all the variables

-3c-(6c-24)+46=0

We get rid of parentheses

-3c-6c+24+46=0

We add all the numbers together, and all the variables

-9c+70=0

We move all terms containing c to the left, all other terms to the right

-9c=-70

c=-70/-9

c=7+7/9

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