48-(3c+4)=4(c+6)+c

Solution for 48-(3c+4)=4(c+6)+c equation:

48-(3c+4)=4(c+6)+c

We move all terms to the left:

48-(3c+4)-(4(c+6)+c)=0

We get rid of parentheses

-3c-(4(c+6)+c)-4+48=0


We calculate terms in parentheses: -(4(c+6)+c), so:

4(c+6)+c

We add all the numbers together, and all the variables

c+4(c+6)

We multiply parentheses

c+4c+24

We add all the numbers together, and all the variables

5c+24

Back to the equation:

-(5c+24)


We add all the numbers together, and all the variables

-3c-(5c+24)+44=0

We get rid of parentheses

-3c-5c-24+44=0

We add all the numbers together, and all the variables

-8c+20=0

We move all terms containing c to the left, all other terms to the right

-8c=-20

c=-20/-8

c=2+1/2