48-(3c+4)=4(c+7+c)

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Solution for 48-(3c+4)=4(c+7+c) equation: 



48-(3c+4)=4(c+7+c)

We move all terms to the left:

48-(3c+4)-(4(c+7+c))=0

We add all the numbers together, and all the variables

-(3c+4)-(4(2c+7))+48=0

We get rid of parentheses

-3c-(4(2c+7))-4+48=0



We calculate terms in parentheses: -(4(2c+7)), so:

4(2c+7)

We multiply parentheses

8c+28

Back to the equation:

-(8c+28)



We add all the numbers together, and all the variables

-3c-(8c+28)+44=0

We get rid of parentheses

-3c-8c-28+44=0

We add all the numbers together, and all the variables

-11c+16=0

We move all terms containing c to the left, all other terms to the right

-11c=-16

c=-16/-11

c=1+5/11

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