48-(3c+4)=4c+5+c

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Solution for 48-(3c+4)=4c+5+c equation: 



48-(3c+4)=4c+5+c

We move all terms to the left:

48-(3c+4)-(4c+5+c)=0

We add all the numbers together, and all the variables

-(3c+4)-(5c+5)+48=0

We get rid of parentheses

-3c-5c-4-5+48=0

We add all the numbers together, and all the variables

-8c+39=0

We move all terms containing c to the left, all other terms to the right

-8c=-39

c=-39/-8

c=4+7/8

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