48-10=b+3b-2b

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Solution for 48-10=b+3b-2b equation: 



48-10=b+3b-2b

We move all terms to the left:

48-10-(b+3b-2b)=0

We add all the numbers together, and all the variables

-(+2b)+48-10=0

We add all the numbers together, and all the variables

-(+2b)+38=0

We get rid of parentheses

-2b+38=0

We move all terms containing b to the left, all other terms to the right

-2b=-38

b=-38/-2

b=+19

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