48-4(x+5)=12+2(x-10)

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Solution for 48-4(x+5)=12+2(x-10) equation:



48-4(x+5)=12+2(x-10)
We move all terms to the left:
48-4(x+5)-(12+2(x-10))=0
We multiply parentheses
-4x-(12+2(x-10))-20+48=0
We calculate terms in parentheses: -(12+2(x-10)), so:
12+2(x-10)
determiningTheFunctionDomain 2(x-10)+12
We multiply parentheses
2x-20+12
We add all the numbers together, and all the variables
2x-8
Back to the equation:
-(2x-8)
We add all the numbers together, and all the variables
-4x-(2x-8)+28=0
We get rid of parentheses
-4x-2x+8+28=0
We add all the numbers together, and all the variables
-6x+36=0
We move all terms containing x to the left, all other terms to the right
-6x=-36
x=-36/-6
x=+6

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