48-5(1-n)=3(4+2n)-2

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Solution for 48-5(1-n)=3(4+2n)-2 equation: 



48-5(1-n)=3(4+2n)-2

We move all terms to the left:

48-5(1-n)-(3(4+2n)-2)=0

We add all the numbers together, and all the variables

-5(-1n+1)-(3(2n+4)-2)+48=0

We multiply parentheses

5n-(3(2n+4)-2)-5+48=0



We calculate terms in parentheses: -(3(2n+4)-2), so:

3(2n+4)-2

We multiply parentheses

6n+12-2

We add all the numbers together, and all the variables

6n+10

Back to the equation:

-(6n+10)



We add all the numbers together, and all the variables

5n-(6n+10)+43=0

We get rid of parentheses

5n-6n-10+43=0

We add all the numbers together, and all the variables

-1n+33=0

We move all terms containing n to the left, all other terms to the right

-n=-33

n=-33/-1

n=+33

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