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48-5(b-4)=2(6b+2)+20
We move all terms to the left:
48-5(b-4)-(2(6b+2)+20)=0
We multiply parentheses
-5b-(2(6b+2)+20)+20+48=0
We calculate terms in parentheses: -(2(6b+2)+20), so:We add all the numbers together, and all the variables
2(6b+2)+20
We multiply parentheses
12b+4+20
We add all the numbers together, and all the variables
12b+24
Back to the equation:
-(12b+24)
-5b-(12b+24)+68=0
We get rid of parentheses
-5b-12b-24+68=0
We add all the numbers together, and all the variables
-17b+44=0
We move all terms containing b to the left, all other terms to the right
-17b=-44
b=-44/-17
b=2+10/17
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