48-8(n-2)=4(n+4)

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Solution for 48-8(n-2)=4(n+4) equation: 



48-8(n-2)=4(n+4)

We move all terms to the left:

48-8(n-2)-(4(n+4))=0

We multiply parentheses

-8n-(4(n+4))+16+48=0



We calculate terms in parentheses: -(4(n+4)), so:

4(n+4)

We multiply parentheses

4n+16

Back to the equation:

-(4n+16)



We add all the numbers together, and all the variables

-8n-(4n+16)+64=0

We get rid of parentheses

-8n-4n-16+64=0

We add all the numbers together, and all the variables

-12n+48=0

We move all terms containing n to the left, all other terms to the right

-12n=-48

n=-48/-12

n=+4

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