48.99+0.99(n+1)=1.29+1.29(n+1)

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Solution for 48.99+0.99(n+1)=1.29+1.29(n+1) equation:



48.99+0.99(n+1)=1.29+1.29(n+1)
We move all terms to the left:
48.99+0.99(n+1)-(1.29+1.29(n+1))=0
We multiply parentheses
0.99n-(1.29+1.29(n+1))+0.99+48.99=0
We calculate terms in parentheses: -(1.29+1.29(n+1)), so:
1.29+1.29(n+1)
determiningTheFunctionDomain 1.29(n+1)+1.29
We multiply parentheses
1.29n+1.29+1.29
We add all the numbers together, and all the variables
1.29n+2.58
Back to the equation:
-(1.29n+2.58)
We add all the numbers together, and all the variables
0.99n-(1.29n+2.58)+49.98=0
We get rid of parentheses
0.99n-1.29n-2.58+49.98=0
We add all the numbers together, and all the variables
-0.3n+47.4=0
We move all terms containing n to the left, all other terms to the right
-0.3n=-47.4
n=-47.4/-0.3
n=+158

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