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480=(480/x-20)(x+4)
We move all terms to the left:
480-((480/x-20)(x+4))=0
Domain of the equation: x-20)(x+4))!=0We multiply parentheses ..
x∈R
-((+480x^2+1920x-20x-80))+480=0
We calculate terms in parentheses: -((+480x^2+1920x-20x-80)), so:We get rid of parentheses
(+480x^2+1920x-20x-80)
We get rid of parentheses
480x^2+1920x-20x-80
We add all the numbers together, and all the variables
480x^2+1900x-80
Back to the equation:
-(480x^2+1900x-80)
-480x^2-1900x+80+480=0
We add all the numbers together, and all the variables
-480x^2-1900x+560=0
a = -480; b = -1900; c = +560;
Δ = b2-4ac
Δ = -19002-4·(-480)·560
Δ = 4685200
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{4685200}=\sqrt{400*11713}=\sqrt{400}*\sqrt{11713}=20\sqrt{11713}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-1900)-20\sqrt{11713}}{2*-480}=\frac{1900-20\sqrt{11713}}{-960} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-1900)+20\sqrt{11713}}{2*-480}=\frac{1900+20\sqrt{11713}}{-960} $
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