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480=4x*3x
We move all terms to the left:
480-(4x*3x)=0
We add all the numbers together, and all the variables
-(+4x*3x)+480=0
We get rid of parentheses
-4x*3x+480=0
Wy multiply elements
-12x^2+480=0
a = -12; b = 0; c = +480;
Δ = b2-4ac
Δ = 02-4·(-12)·480
Δ = 23040
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{23040}=\sqrt{2304*10}=\sqrt{2304}*\sqrt{10}=48\sqrt{10}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-48\sqrt{10}}{2*-12}=\frac{0-48\sqrt{10}}{-24} =-\frac{48\sqrt{10}}{-24} =-\frac{2\sqrt{10}}{-1} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+48\sqrt{10}}{2*-12}=\frac{0+48\sqrt{10}}{-24} =\frac{48\sqrt{10}}{-24} =\frac{2\sqrt{10}}{-1} $
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