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480=x(x+14)
We move all terms to the left:
480-(x(x+14))=0
We calculate terms in parentheses: -(x(x+14)), so:We get rid of parentheses
x(x+14)
We multiply parentheses
x^2+14x
Back to the equation:
-(x^2+14x)
-x^2-14x+480=0
We add all the numbers together, and all the variables
-1x^2-14x+480=0
a = -1; b = -14; c = +480;
Δ = b2-4ac
Δ = -142-4·(-1)·480
Δ = 2116
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{2116}=46$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-14)-46}{2*-1}=\frac{-32}{-2} =+16 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-14)+46}{2*-1}=\frac{60}{-2} =-30 $
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