480t=660(t-1/12)

Solution for 480t=660(t-1/12) equation:

480t=660(t-1/12)

We move all terms to the left:

480t-(660(t-1/12))=0

We add all the numbers together, and all the variables

480t-(660(+t-1/12))=0

We multiply all the terms by the denominator


480t*12))-(660(+t-1=0

We add all the numbers together, and all the variables

t+480t*12))-(660(-1=0

Wy multiply elements

5760t^2+t-1=0

a = 5760; b = 1; c = -1;
Δ = b2-4ac
Δ = 12-4·5760·(-1)
Δ = 23041
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1)-\sqrt{23041}}{2*5760}=\frac{-1-\sqrt{23041}}{11520}
$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1)+\sqrt{23041}}{2*5760}=\frac{-1+\sqrt{23041}}{11520}
$