483+2x=x2

Solution for 483+2x=x2 equation:

483+2x=x2

We move all terms to the left:

483+2x-(x2)=0

We add all the numbers together, and all the variables

-1x^2+2x+483=0

a = -1; b = 2; c = +483;
Δ = b2-4ac
Δ = 22-4·(-1)·483
Δ = 1936
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1936}=44$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(2)-44}{2*-1}=\frac{-46}{-2}
=+23
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(2)+44}{2*-1}=\frac{42}{-2}
=-21
$