48=(6x-10)(2x)

Solution for 48=(6x-10)(2x) equation:

48=(6x-10)(2x)

We move all terms to the left:

48-((6x-10)(2x))=0


We calculate terms in parentheses: -((6x-10)2x), so:

(6x-10)2x

We multiply parentheses

12x^2-20x

Back to the equation:

-(12x^2-20x)


We get rid of parentheses

-12x^2+20x+48=0

a = -12; b = 20; c = +48;
Δ = b2-4ac
Δ = 202-4·(-12)·48
Δ = 2704
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{2704}=52$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(20)-52}{2*-12}=\frac{-72}{-24}
=+3
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(20)+52}{2*-12}=\frac{32}{-24}
=-1+1/3
$